How do you check on Vista if .exe file is 32-bit or 64-bit?

Assume 64-bit Vista and assume that you do not want to run the .exe
file
Is there a utility that will read an .exe file and provide specifics
like 32-bit or 64-bit code?

I have one utility that will provide a lot of info included in .exe
file but none
indicates if the code was compiled as 32-bit or 64-bit

 

Hello Gee,

In the 64-bit Vista Task Manager (CTRL+SHIFT+ESCAPE), in the Processes
tab, you can look to see if the running EXE file has "*32" next to it.
If it does, then it is a 32-bit program. If not, then it is a 64-bit
program.

Hope this helps,
Shawn

gee9782;888172 Wrote: <!--coloro:blue--><span style="color:blue <!--/coloro-->
> Assume 64-bit Vista and assume that you do not want to run the .exe
> file
> Is there a utility that will read an .exe file and provide specifics
> like 32-bit or 64-bit code?
>
> I have one utility that will provide a lot of info included in .exe
> file but none
> indicates if the code was compiled as 32-bit or 64-bit<!--colorc--><!--/colorc-->


--
Brink

*There are no dumb questions, just the people that do not ask
them.*
'*Windows 7 Forums*'
() *and* '*::Vista Forums::*'
()
*Please post feedback to help others.*

 

On Nov 17, 12:53 am, Brink <gu...@unknown-email.com> wrote:<!--coloro:blue--><span style="color:blue <!--/coloro-->
> Hello Gee,
>
> In the 64-bit Vista Task Manager (CTRL+SHIFT+ESCAPE), in the Processes
> tab, you can look to see if the running EXE file has "*32" next to it.<!--colorc--><!--/colorc-->

My question is not about a running/executing program.
My question is about an .exe file without ever running/executing it.

 

Since there is work involved in producing a 64 bit version of a program, in
a world where almost all the OSs are 32 bit,
all programs advertise when their program is written for 64 bit. It's a
selling point.

Check the user requirements for any program.
When you don't find it, it'll be 32 bit.

<gee9782@yahoo.com> wrote in message
news:65a475fa-19c8-4eb2-88f2-0e33e274a545@o4g2000pra.googlegroups.com...
On Nov 17, 12:53 am, Brink <gu...@unknown-email.com> wrote:<!--coloro:blue--><span style="color:blue <!--/coloro-->
> Hello Gee,
>
> In the 64-bit Vista Task Manager (CTRL+SHIFT+ESCAPE), in the Processes
> tab, you can look to see if the running EXE file has "*32" next to it.<!--colorc--><!--/colorc-->

My question is not about a running/executing program.
My question is about an .exe file without ever running/executing it.

 

"Ralph" <aj531@ncf.ca> wrote in message news:#yREnEKSJHA.3880@TK2MSFTNGP04.phx.gbl...<!--coloro:blue--><span style="color:blue <!--/coloro-->
> Since there is work involved in producing a 64 bit version of a program, in a world
> where almost all the OSs are 32 bit,
> all programs advertise when their program is written for 64 bit. It's a selling
> point.<!--colorc--><!--/colorc-->

Yes but is there a programmatic way to tell if an executable
is 32- or 64-bit without running it? Maybe something in the header?

Tom Lake

 

There is a GNU-util called "file". I think you could either download
'GNU Coreutils for Windows'
()
or you can compile your own version of "file" using 'Cygwin'
().

The usage of "file" is very easy; just type:

Code:
--------------------
file {filename}
--------------------


It'll output something like that (on Linux):

Code:
--------------------
{filename}: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), for GNU/Linux 2.6.8, dynamically linked (uses shared libs), stripped

--------------------


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